molexsayole497 molexsayole497
  • 22-01-2020
  • Engineering
contestada

an electric heater consumes 3.6MJ when connected to a 250V supply for 40minutes find the power rating of the heater and the current taken from supply​

Respuesta :

Abyola Abyola
  • 30-01-2020

Answer:

Power rating of heater=1.5kw

Current taken from the supply=6A

Explanation:

Power(P)=Energy/Time

Where, electrical energy=3.6*10^6J and Time=40mins=40*60s

P=3.6*10^6J/40*60s

P=1500J/s or 1500watts

P=1.5kw

Current supply:

P=VI

Where, power(P)=1500watts,Voltage supply (V)=250volts, and current(I)=?

Making current (I) the subject of the formula :

I=P/V

I=1500watts/250volts=6A

Therefore, current taken from the supply is 6A.

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