VannothyZacJo6ell VannothyZacJo6ell

21-06-2016
Chemistry

contestada

Mole of Al 3.26*10^24 atoms of Al

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gesubakieva gesubakieva

21-06-2016

n=N/Na=3.26*10^24/6.02*10^23=5.41mol.

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