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Hydrocarbons, compounds containing only carbon and hydrogen, are important in fuels. The heat of combustion of cyclopropane, C3H6, is 499.8 kcal/mol. Write a balanced equation for the complete combustion of cyclopropane. How much energy is released during the complete combustion of 497 grams of cyclopropane? kcal

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Answer:

The complete combustion of cyclopropane is:

2C₃H₆  +  9O₂  →  6CO₂  +  6H₂O

5914.3kcal are realeased in the  combustion of 497 g of cyclopropane

Explanation:

Heat of combustion = 499.8 kcal/mol

This data means that 1 mol of C₃H₆ release 499.8 kcal.

Let's convert the mass to moles (mass / molar mass)

497 g / 42g/mol = 11.83 moles

Let's make a rule of three:

1 mol ____ 499.8

11.83 moles _____ (11.83  .499.8)/1 =5914.3kcal

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