Step-by-step explanation:
[tex]C(x)=4x^2-3\\\\C(0),\ C(-1),\ C(-2),\ C\left(-\dfrac{3}{2}\right)\\\\\text{Substitute each value}\ \left\{0, -1, -2, -\frac{3}{2}\right\}\ \text{instead}\ C(x):\\\\C(0)=4(0^2)-3=4(0)-3=0-3=-3\\\\C(-1)=4(-1)^2-3=4(1)-3=4-3=1\\\\C(-2)=4(-2)^2-3=4(4)-3=16-3=13\\\\C\left(-\dfrac{3}{2}\right)=4\left(-\dfrac{3}{2}\right)^2-3=4\left(\dfrac{9}{4}\right)-3=9-3=6[/tex]
