The position of a particle as it moves along the x axis is given for t>0 by x=(t^3 - 3t^2 +6t)m , where t in sec.Where id the particle wen it achieves its minimum speed (after t=0)?

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y1a5smithsichacarays y1a5smithsichacarays

23-06-2016
Mathematics

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The position of a particle as it moves along the x axis is given for t>0 by x=(t^3 - 3t^2 +6t)m , where t in sec.Where id the particle wen it achieves its minimum speed (after t=0)?

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meerkat18 meerkat18 · Answer 1 · 2016-07-06T21:29:14+02:00

meerkat18 meerkat18

06-07-2016

We are given with the equation of the distance of a particle expressed in x=(t^3 - 3t^2 -6t). To get the distance where minimum speed is achieved, we get the first derivative of the equation and equate to zero. hence, dx /dt = 3t^2 - 6t - 6 = 0. t is equal to 2.73 sec. The distance then after substituting to the original equation equal to 14.37 meters.

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