Answer:
Option B, x = [tex]\frac{1 + ln(3)}{4}[/tex]
Step-by-step explanation:
e^4x-1 = 3
ln both side
ln(e^4x - 1) = ln(3)
ln(e) = 1
4x - 1 + 1 = ln(3) + 1
4x / 4 = (ln(3) + 1) / 4
x = [tex]\frac{ln(3) + 1}{4}[/tex]
Answer: Option B, x = [tex]\frac{1 + ln(3)}{4}[/tex]
