kimberlyocallaghan
kimberlyocallaghan kimberlyocallaghan
  • 26-02-2020
  • Mathematics
contestada

Rearranging literal equations ASAP REALLY NEED HELP PLEASE

Rearranging literal equations ASAP REALLY NEED HELP PLEASE class=

Respuesta :

yasmitadp yasmitadp
  • 26-02-2020

Answer:

q = [tex]\frac{-2}{5}[/tex]

Step-by-step explanation:

(i) [tex](\frac{-6p + 10q}{10q - 1})^{ \frac{1}{3} }[/tex] = 2

Cubing we get

[tex]\frac{-6p + 10q}{10q - 1} = 2^{3}[/tex]

-6p + 10q = 80q - 8

-6p + 8 = 70q

[tex]q = \frac{-6p + 8}{70}[/tex]

(ii) If p = 6 then

  q = [tex]\frac{-28}{70}[/tex]  = [tex]\frac{-2}{5}[/tex]

 

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