Answer:
249.44g of CaCl2
Explanation:
First, we need to write a balanced equation for the reaction. This is illustrated below:
2AlCl3 + 3Ca —> 3CaCl2 + 2Al
Molar Mass of AlCl3 = 27 + (3x35.5) = 27 + 106.5 = 133.5g/mol
Mass of AlCl3 from the balanced equation = 2 x 133.5g = 267g
Molar Mass of CaCl2 = 40 + (2 x 35.5) = 40 + 71 = 111g/mol
Mass of CaCl2 from the balanced equation = 3 x 111 = 333g
From the equation,
133.5g of AlCl3 produced 333g of CaCl2
Therefore, 100g of AlCl3 will produce = (100 x 333)/133.5 = 249.44g of CaCl2.
