Answer:
Option C. 0.23 molar
Explanation:
The following data were obtained from the question given:
C1 = 0.5 M
V1 = 340mL
V2 = since 400mL was added to the original volume, therefore = 340 + 400 = 740mL
C2 =?
The concentration of the diluted solution can be calculated by using the following:
C1V1 = C2V2
0.5 x 340 = C2 x 740
Divide both side by 740
C2 = (0.5 x 340) / 740
C2 = 0.23M
Therefore, the new concentration of the solution is 0.23M
