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Answer:

Step-by-step explanation:

[tex]\theta=30^\circ=\frac{30}{180} \pi =\frac{\pi }{6}\\l=r \theta\\JK=2 \times \frac{\pi }{6} =\frac{\pi }{3} \approx 1.047circumference=2\pi r=2 \times \pi \times 2=4 \pi \approx 12.57 ~ft[/tex]

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