Answer:
[tex]p=\frac{1}{12}[/tex]
Step-by-step explanation:
-The sample space of a coin toss is:
{ Head , Tail }
-The sample space of a dice is:
{1,2,3,4,5,6}
-The sample space of the two simultaneous events is:
{Head,1} , {Head,2} , {Head,3} , {Head,4} , {Head,5} , {Head,6} , {Tail,1} , {Tail,2} , {Tail,3} , {Tail,4} , {Tail,5} , {Tail,6}
=>Our desired result from the sample space is {Head,3}
The probability,[tex]p=\frac{1}{12}[/tex]
