[tex]e=\frac{T- n}{T+n}[/tex]
Step-by-step explanation:
Here we have , to make e as subject of formula and given expression is:
[tex]T = \frac{n(1+e)}{(1-e)}[/tex]
⇒ [tex]T = \frac{n(1+e)}{(1-e)}[/tex]
⇒ [tex]T(1-e) = \frac{n(1+e)}{(1-e)}(1-e)[/tex]
⇒ [tex]T(1-e) = n(1+e)[/tex]
⇒ [tex]T-T(e)= n+n(e)[/tex]
⇒ [tex]T-T(e)+T(e)= n+n(e)+T(e)[/tex]
⇒ [tex]T= n+e(T+n)[/tex]
⇒ [tex]T- n=e(T+n)[/tex]
⇒ [tex]e=\frac{T- n}{T+n}[/tex]
Therefore, [tex]e=\frac{T- n}{T+n}[/tex] .
