chblewis chblewis
  • 25-03-2020
  • Mathematics
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3x-8<=23 AND -4x+26>=6

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igoroleshko156
igoroleshko156 igoroleshko156
  • 25-03-2020

Answer:

Step 1:  Solve for x in the first equation

[tex]3x-8+8\leq 23+8[/tex]

[tex]3x\leq 31[/tex]

[tex]3x/3\leq 31/3[/tex]

[tex]x\leq \frac{31}{3}[/tex]

Step 2:  Solve for x in the second equation

[tex]-4x + 26-26 \geq 6-26[/tex]

[tex]-4x\geq -20[/tex]

[tex]-4x/-4\geq -20/-4[/tex]

Since you divide by a negative, you must flip the sign.

[tex]x\leq 5[/tex]

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