tthalism9in1e
tthalism9in1e
25-07-2016
Mathematics
contestada
Solve 4(x - 3) - 2(x - 1) > 0.
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dalendrk
dalendrk
25-07-2016
4(x - 3) - 2(x - 1) > 0
4x - 12 - 2x + 2 > 0
2x - 10 > 0 |add 10 to both sides
2x > 10 |divide both sides by 2
x > 10 ⇒ x ∈ (10; ∞)
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