Respuesta :

dalendrk
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}\\\\(-8;\ 2)\to x_1=-8\ and\ y_1=2\\(2;\ 6)\to x_2=2\ and\ y_2=6\\\\m=\dfrac{6-2}{2-(-8)}=\dfrac{4}{2+8}=\dfrac{4}{10}=0.4[/tex]