noraespi5600 noraespi5600
  • 22-04-2020
  • Physics
contestada

The half-life of phosphorus-32 is 14.26 days. Calculate its decay constant.

Respuesta :

muhammadtalhabinyous
muhammadtalhabinyous muhammadtalhabinyous
  • 22-04-2020

Answer:

5.62 x 10^-7 sec-1

Explanation:

Converting days to seconds:

14.26 x 24x60x60= 1.27 x 10^6

Half life= 0.693 / Decay constant

so

Decay constant = 0.693/1.27x 10^6

= 5.62 x 10^-7

Answer Link

Otras preguntas

what effects on sectionalism did the industrial revolution have?
How do I factor our 36m3-6m2p2-6mp+p3?
what happens to an Atom when it gains two electrons
how many pairs of chromosomes are in a body cell of a macaw
divide 500 in a ratio of 3:7
Why was the first pyramid built
A theatre sells 467 tickets Some other people then buy another 118 tickets If the theatre holds 1060 people how many places are left un-sold?
list 3 human activities that release chemicals that produce acid rain.
When two hydrogen atoms bond, the positive nucleus of one atom attracts the
The factor that affects how easily an electron can be removed from an atom is the A. surrounding atoms. B. temperature of the environment. C. size of the atom.