jeremiahhernandez824 jeremiahhernandez824
  • 24-04-2020
  • Mathematics
contestada

Rewrite the equation of this circle in standard form. Identify the center and radius.

Rewrite the equation of this circle in standard form Identify the center and radius class=

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valleybritney
valleybritney valleybritney
  • 24-04-2020

Answer:

Center (3,13)

Radius r = 4

Step-by-step explanation:

Circle equation: [tex](x-h)^2 + (y-k)^2 = r^2[/tex]

Given: [tex]y^2+x^2-6x-26y=-162[/tex]

Group x-term and y-term together:

[tex](x^2-6x) + (y^2-26y) = -162[/tex]

Complete the square for x-term, y-term using formula [tex]"x^2+(2a)x+a^2 = (x+a)^2"[/tex]

[tex](x^2-(2)(3)x+(3)^2) + (y^2-(2)(13)y+(13)^2)=-162+(3)^2+(13)^2[/tex]

[tex](x-3)^2 + (y-13)^2=16[/tex]

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