Answer:
(-x-2) (-2x -3)=0
=>[-(x +2)] [-(2x+3)]=0
=>(x + 2)(2x +3)=0
=>x =-2 or,x=-3/2
smaller x=-2
larger x =-3/2
(-x-2)(-2x-3)=0
-x-2=0; x= -2
-2x-3=0; x= -3/2
-2<-3/2
larger x=-3/2
