Respuesta :

luana
[tex] \left \{ {{11u=5v+35} \atop {8v=6u+62}} \right. \\\\ \left \{ {{11u-5v=35\ \ \ |\cdot8} \atop {-6u+8v=62\ \ \ |\cdot5}} \right. \\\\ \left \{ {{88u-40v=280} \atop {-30u+40v=310}} \right. \\+------\\\\58u=590\ \ \ |:58\\u=\frac{590}{58}=\frac{295}{29}=10\frac{5}{29}\\\\8v=6\cdot\frac{295}{29}+35\\8v=\frac{1770}{29}+\frac{1015}{29}\\8v=\frac{2785}{29}\ \ \ \ |\cdot\frac{1}{8}\\v=\frac{2785}{232}=12\frac{1}{232}[/tex]

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