Answer:
[tex]2x^2 + 100 =0[/tex]
Comparing equation to [tex]ax^2+bx+c =0[/tex]
a = 2
b= 0
c= 100
[tex]x = \displaystyle \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
[tex]x = \displaystyle \frac{0 \pm \sqrt{0 - 4 × 2 × 100}}{2×2}[/tex]
[tex]x = \displaystyle \frac{\pm 20\sqrt{-2}}{4}[/tex]
[tex]x = \pm 5\sqrt2 i[/tex]
Thus the answer is (b)
