imanwisaw
imanwisaw imanwisaw
  • 21-06-2020
  • Mathematics
contestada

Simplify
2
[tex] \s \sqrt{x { } ^{2} -4x + 4} [/tex]
x^2 - 4x + 4 if x<2​

Respuesta :

SvetkaChem
SvetkaChem SvetkaChem
  • 21-06-2020

Answer:

2 - x

Step-by-step explanation:

x² - 4x + 4

4 = (-2)*(-2)

- 4 = -2 -2

x² - 4x + 4  = (x - 2)(x - 2) = (x - 2)²

√[(x - 2)²] = |x - 2|

or abs(x-2) because value under the root should be positive

if x< 2, then |x-2| = -(x-2) = 2 -x

Answer Link
dannielle
dannielle dannielle
  • 21-06-2020

Answer:

2-x

Step-by-step explanation:

Vx^2-4x+4=Vx^2-2*x*2+2^2=V(x-2)^2=|x-2|

if x<2 then x-2<0 and |x-2|=2-x

Answer Link

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