Answer:
[tex]\dfrac{k^2+5k}{4k^2}[/tex]
Step-by-step explanation:
A suitable common denominator is 4k^2. (This eliminates the first and last choices.)
[tex]\dfrac{3k}{k^2}+\dfrac{k-7}{4k}=\dfrac{4(3k)}{4(k^2)}+\dfrac{k(k-7)}{k(4k)}\\\\=\dfrac{12k+k^2-7k}{4k^2}=\boxed{\dfrac{k^2+5k}{4k^2}}[/tex]
