imshagun1
imshagun1 imshagun1
  • 24-06-2020
  • Mathematics
contestada

Will mark brainliest solve for x 32^(x +4) = 64^(2x–1)

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 24-06-2020

Answer:

26/7 =x

Step-by-step explanation:

32^(x +4) = 64^(2x–1)

Rewrite each as a power of 2

32 = 2^5   and 64 = 2^6

2^5^(x +4) = 2^6^(2x–1)

We know a^b^c = a^(b*c)

2^(5*(x +4)) = 2^(6*(2x–1))

The bases are the same so the exponents are the same

5*(x +4) = 6*(2x–1)

Distribute

5x +20 = 12x -6

Subtract 5x

20 = 7x -6

Add 6 to each side

26 = 7x

Divide by 7

26/7 =x

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