Answer:
B
Step-by-step explanation:
[tex]-2x^2-4x=6 \\\\\\-2x^2-4x-6=0\\\\\\2x^2+4x+6=0\\\\\\x=\dfrac{-4\pm\sqrt{16-48}}{4}= \\\\\\\dfrac{-4\pm4\sqrt{2}i}{4}=\\\\\\-1\pm \sqrt{2}i[/tex]
Therefore, the correct answer is choice B. Hope this helps!
