The pyramid consists of 4 congruent triangular faces, and 1 square base.
Area of 1 triangular face:
1/2 * (5 in)/2 * (5.6 in) = 7 in^2
Area of base:
(5 in)^2 = 25 in^2
Then the total surface area is
4 * (7 in^2) + 25 in^2 = (28 + 25) in^2 = 53 in^2
