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22-07-2020
Mathematics

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Given: DF and DE are midsegments of ∆ABC Prove: DE= 1/2 AC (PLEASE HELP)

Given DF and DE are midsegments of ABC Prove DE 12 AC PLEASE HELP class=

Given DF and DE are midsegments of ABC Prove DE 12 AC PLEASE HELP class=

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22-07-2020

Answer:

The correct answer is D because we proved that the triangles ΔDBE and ΔADF are congruent so that means that DE = segment A F because of CPCTC.

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