Answer: f(x) = -3x^2 + 3x - 2
Explain: x of vertex: [tex]x[/tex] = [tex](-\frac b{2}{a} )[/tex] = [tex]-\frac{3}{-6} = \frac{1}{2}[/tex]
y of vertex: y = [tex]f (\frac{1}{2} ) = - \frac{3}{4} + \frac{3}{2} -2=-\frac{5}{4}[/tex]
y-intercept: y = -2
x-intercept: y = 0
D = b[tex]^[/tex]^2 - 4ac = 9 - 24 = - 15 <0. There are no real roots (no x-intercepts) because D<0.
Since a <0, parabola opens downward. The parabola is below the x-axis
