Step-by-step explanation:
Hey, there!!
Given that,
[tex] \frac{ {x}^{2} - 9 }{x + 3} [/tex]
{ we can write (a^2-4) as (a^2 - 2^2) also as (x^2- 9) can be written as (x^2 - 3^2)}.
[tex] \frac{ {x}^{2} - {3}^{2} }{x + 3} [/tex]
We have a^2-b^2= (a+b) (a-b), so keep same formula on it.
[tex] \frac{(x + 3)(x - 3)}{(x + 3)} [/tex]
(x+3) in numerator and denominator gets cancelled,
[tex](x - 3)[/tex]
Therefore, (x-3) is the final value.
Hope it helps...
