secondbeaver
secondbeaver secondbeaver
  • 22-08-2020
  • Mathematics
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d = b^2 -4ac solve for a 2/3 (x-18y) = 6y solve for x

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Space
Space Space
  • 22-08-2020

Answer:

a = [tex]\frac{b^2-d}{4c}[/tex]

x = 27y

Step-by-step explanation:

Order of Operations: BPEMDAS

Question 1

Step 1: Write out discriminant

d = b² - 4ac

Step 2: Subtract b² on both sides

d - b² = -4ac

Step 3: Divide both sides by -1

b² - d = 4ac

Step 4: Divide both sides by 4c

a = [tex]\frac{b^2-d}{4c}[/tex]

Question 2

Step 1: Write out equation

2/3(x - 18y) = 6y

Step 2: Distribute parenthesis

2/3x - 12y = 6y

Step 3: Isolate x by adding 12y on both sides

2/3x = 18y

Step 4: Divide both sides by 2/3

x = 27y

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