Answer:
Step-by-step explanation:
Hello, you know that for a and b real numbers
(ab=0) <=> (a = 0 or b = 0)
[tex]f(x)=(2^x-1)(x^2+2x-3)=9\\\\<=> 2^x-1 = 0 \ or \ x^2+2x-3=0[/tex]
First, let's check [tex]x^2+2x-3=0[/tex]
The sum of the roots is -2=-3+1 and the product is -3=-3*1
So we can factorise by (x+3)(x-1)
And the roots are -3 and 1
Now, let's check the first term
[tex]2^x-1=0<=>2^x=1=2^0<=>x=0[/tex]
So the roots are 0, 1 , -3
Thanks
