dadspal04 dadspal04
  • 21-09-2020
  • Mathematics
contestada

solve for x 2x^2 + x - 1 = 2

Respuesta :

jimrgrant1 jimrgrant1
  • 21-09-2020

Answer:

x = - [tex]\frac{3}{2}[/tex], x = 1

Step-by-step explanation:

Given

2x² + x - 1 = 2 ( subtract 2 from both sides )

2x² + x - 3 = 0 ← in standard form

(2x + 3)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = - [tex]\frac{3}{2}[/tex]

x - 1 = 0 ⇒ x = 1

Answer Link
mykiahgriffiths
mykiahgriffiths mykiahgriffiths
  • 21-09-2020

Answer:

x= -3/2 or 1

Step-by-step explanation:

2x^2 +x-1=2

2x^2 +x-3=0

(2x+3)(x-1)=0

2x+3=0   x-1=0

2x= -3     x=1

x= -3/2    x=1

Answer Link

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