Given :
P(-9, -4), Q(-7, -1), R(-2, 5), S(-6, -1).
To Find :
The slope of line PQ.
Solution :
We know , slope is given by :
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}\\\\m=\dfrac{-9-(-7)}{-4-(-1)}\\\\m=\dfrac{2}{3}[/tex]
Therefore, the slope of line PQ is 2/3.
Hence, this is the required solution.
