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23-09-2016
Mathematics

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write the expression in 8^-2/3 in radical notation b evaluate the expression

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25-09-2016

[tex]8^{-\frac{2}{3}}=\frac{1}{8^\frac{2}{3}}=\frac{1}{(\sqrt[3]{8})^2}\\ \\ \\ \frac{1}{(\sqrt[3]{8})^2} = \frac{1}{2^2}=\frac{1}{4}[/tex]

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