Answer:
f(x) = 3x^3 + 3x^2 - 6x.
Step-by-step explanation:
Let:
f(x) = x(x - 1)(x + 2)
= x(x^2 + x - 2)
= x^3 + x^2 - 2x - this might be the answer or it might be some multiple of this.
Now f(2) = 24 so
24 = a(2^3 + 2^2 - 2(2)) where a is a constant.
24 = 8a
a = 3
So the function is
3( x^3 + x^2 - 2x)
= 3x^3 + 3x^2 - 6x.
