g(x) = 1/x - 2
g^(-1) => x = 1/g(x) - 2
g^(-1) => x + 2 = 1/g(x)
g^(-1) => g(x)(x + 2) = 1
g^(-1) => g(x) = 1/(x + 2)
Answer: D. g^(-1) = 1/(x + 2)
