Respuesta :

SageRage

Answer:

[tex](x+1)^2=4[/tex]

Step-by-step explanation:

  • [tex]3+x=x^2+3x[/tex] is our equation
  • first, get all the x terms on one side so the equation equals a constant number
  • [tex]3+x-(x)=x^2+3x-x\\3=x^2+2x\\x^2+2x=3[/tex]
  • Then add to both sides the square of half of the coefficient of x : the coefficient of x here is 2 so
  • the square of half of 2 is [tex](1)^2[/tex] then
  • [tex]x^2+2x+(1)^2=3+(1)^2\\x^2+2x+1=4\\[/tex]
  • If you factor the left side you get
  • [tex]x^2+2x+1=4\\(x+1)^2=4[/tex]

Otras preguntas