roobakalai8606
roobakalai8606 roobakalai8606
  • 21-11-2020
  • Mathematics
contestada

please help me guys this is the question 1) solve 1/3 ( x+y-5) = y-z = 2x-11=9-(x-2z)​

Respuesta :

Аноним Аноним
  • 21-11-2020

Answer:

1/3(x+y-5)=y-z=2x- 11=9-(x+2z)

Step-by-step explanation:

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richmond99
richmond99 richmond99
  • 21-11-2020

1/3(x+y-5)=y-z=2x-11=9-(x-2z)

  • (x+y-5)=3y-3z=6x-33=37-2(x-2x)
  • x+y-5=3y-3z=6x-33=37-3x+6z
  • x-6x+3x=3y-y=-3z-6z=37+33
  • -2x=3y=-9z=70.
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