pastelpoptart79
pastelpoptart79 pastelpoptart79
  • 22-11-2020
  • Mathematics
contestada

Write the following fractions with a denominator 24a^3b^2 and analyze the domains.
1. 2/a^2b^2
2. 5b/8a^3

Respuesta :

oladayoademosu
oladayoademosu oladayoademosu
  • 30-11-2020

Answer:

1. 48a/24a³b²; domain {a ≠ 0 and b ≠ 0}  2. 15b³/24a³b² ; domain {a ≠ 0 and b ≠ 0}

Step-by-step explanation:

1. To have a denominator 24a³b², we multiply 2/a²b² by 24a/24a.

So, 2/a²b² × 24a/24a = 48a/24a³b². For this expression to the valid, the domain is a ≠ 0 and b ≠ 0

2. To have a denominator 24a³b², we multiply 5b/8a³ by 3b²/3b².

So, 5b/8a³ × 3b²/3b². = 15b³/24a³b². For this expression to the valid, the domain is a ≠ 0 and b ≠ 0

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