Answer:
The equation of the line will be:
[tex]y=-\frac{6}{5}x-3[/tex]
Step-by-step explanation:
Given
As the point-slope form is
[tex]y-y_1=m\left(x-x_1\right)[/tex]
[tex]y-3=\frac{-6}{5}\left(x-\left(-5\right)\right)[/tex]
[tex]y-3=\frac{-6}{5}\left(x+5\right)[/tex]
Add 3 to both sides
[tex]y-3+3=-\frac{6}{5}\left(x+5\right)+3[/tex]
[tex]y=-\frac{6}{5}x-3[/tex]
Therefore, the equation of the line will be:
[tex]y=-\frac{6}{5}x-3[/tex]
