cberg1605 cberg1605

23-11-2020
Chemistry

contestada

How many grams of lead would be required to make 119 grams of water

Respuesta :

carrascojesus885 carrascojesus885

23-11-2020

Answer:

(119 g H2O) / (18.01532 g H2O/mol) x (1 mol Pb / 2 mol H2O) x (207.21 g Pb/mol) = 684 g Pb

Explanation:

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RahmaHadi745 RahmaHadi745

26-11-2020

Answer:

684

Explanation:

Answer Link

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