9514 1404 393
Answer:
-1.317
Step-by-step explanation:
[tex]\log_5{15}=x+3 \qquad\text{given}\\\\ \dfrac{\log{15}}{\log{5}}=x+3 \qquad\text{change of base formula}\\\\x=\dfrac{\log{15}}{\log{5}}-3 \qquad\text{subtract 3}\\\\x\approx\dfrac{1.17609}{0.69897}-3\approx 1.683 -3\\\\ \boxed{x\approx -1.317}[/tex]
