Answer:
E=1/2kmv^2
Explanation:
To get the formula...
The dimension of energy is [ M^1 L^2 T^-2]
The dimension of mass [M]=[M^1 L ^0T ^0]
Dimension of velocity[V]=[M ^0 L ^1 T ^−1]
Let [E]=k[M] ^x[V] ^y
K is constant and it remain a dimensionless quantity.
Therefore, M ^1L ^2T ^−2]=k[M ^1L ^0T ^0] x[M ^0L ^1 T ^−1] y
So, x=1,y=2
E= Kmv^2
K=1/2
Therefore E is 1/2kmv^2.
