Given :
A T.V. is measure by its diagonal.
To Find :
If the height of a 60 inch T.V. is 32 inches, what is the width.
Solution :
We know, T.V. is rectangular in shape and angle between two sides of rectangular is 90° .
Let, width of T.V. is x.
Applying Pythagoras theorem in sides, we get :
[tex]height^2 + width^2 = hypotenuse^2\\\\23^2 + x^2 = 60^2\\\\x = \sqrt{3600 -529 }\\\\x = 55.42 \ inches[/tex]
Therefore, width of T.V. is 55.42 inches.
