Answer:
y = -8/5x + 23/5
Step-by-step explanation:
Complete question
Write the equation of the line, in slope-intercept form, that has a slope of -8/5and contains the point (6, –5)
The equation of a line in pint slope form is expressed as;
y - y0 = m(x-x0)
Given
m = -8/5
(x0, y0) = (6, -5)
Substitute into the formula
y - (-5) = -8/5(x-6)
y+5 = -8/5(x-6)
Multiply through by 5
5(y+5) = -8(x-6)
5y + 25 = -8x + 48
5y = -8x +48 - 25
5y = -8x + 23
y = -8/5x + 23/5
Hence the equation in slope intercept form is y = -8/5x + 23/5
