Cassandra2008
Cassandra2008 Cassandra2008
  • 24-01-2021
  • Mathematics
contestada

6X² - 12x + (x-2) = 0
​please help

Respuesta :

Dead3ill
Dead3ill Dead3ill
  • 24-01-2021

Answer:

[tex]x = 2 \: or \: \frac{ - 1}{6} [/tex]

Step-by-step explanation:

Lets open the brackets.

[tex]6 {x}^{2} - 12x + x - 2 = 0[/tex]

Now lets factorise it.

[tex] = > 6 {x}^{2} - 12x + x - 2 = 0[/tex]

[tex] = > 6x(x - 2) + 1(x - 2) = 0[/tex]

[tex] = > (x - 2)(6x + 1) = 0[/tex]

Here x will have two values.

1) [tex]x - 2 = 0[/tex]

[tex] = > x = 2[/tex]

2) [tex]6x + 1 = 0[/tex]

[tex] = > 6x = - 1[/tex]

[tex] = > x = \frac{ - 1}{6} [/tex]

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