Zulla10
Zulla10 Zulla10
  • 25-01-2021
  • Mathematics
contestada

I really need help with this Triangle problem. ​

I really need help with this Triangle problem class=

Respuesta :

Hrishii
Hrishii Hrishii
  • 25-01-2021

Answer:

x = 10

y = 20

Step-by-step explanation:

[tex] \tan \: 30 \degree = \frac{x}{10 \sqrt{3} } \\ \\ \frac{1}{ \sqrt{3} } = \frac{x}{10 \sqrt{3} } \\ \\ \sqrt{3} x = 10 \sqrt{3} \\ \\ x = \frac{10 \sqrt{3} }{ \sqrt{3} } \\ \\ x = 10 \\ \\ \cos 30 \degree = \frac{10 \sqrt{3} }{y} \\ \\ \frac{ \sqrt{3} }{2} = \frac{10 \sqrt{3} }{y} \\ \\ y = 10 \sqrt{3} \times \frac{2}{ \sqrt{3} } \\ \\ y = 10 \times 2 \\ \\ y = 20[/tex]

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