nope47458 nope47458

22-02-2021
Mathematics

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prove that there is only one circle determined by three noncollinear points

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10547414 10547414

22-02-2021

Answer:

O lies on the perpendicular bisector of AB. ... Then, O' will lie on the perpendicular bisector PQ and RS. We know that, two lines cannot intersect at more than one point, So O' must coincide with O. Hence, there is one and only one circle passing through three non collinear points

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pyttnazerine pyttnazerine

22-02-2021

O lies on the profitable day. Oh lord I shall take this gift and hold it with my word amen.

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