Answer:
199.7mL
Explanation:
Using Charles law equation as follows:
V1/T1 = V2/T2
Where;
V1 = initial volume (mL)
T1 = initial temperature (°F)
V2 = final volume (mL)
T2 = final temperature (°F)
According to the information provided in this question, V1 = 135mL, V2 = ?, T1 = 67.6°F, T2 = 100°F
Using V1/T1 = V2/T2
135/67.6 = V2/100
Cross multiply
135 × 100 = 67.6 × V2
13500 = 67.6V2
V2 = 13500/67.6
V2 = 199.704
The new volume in the air in the helium ballon is 199.7mL.
