Answer:
D
Step-by-step explanation:
[tex] \sin(60) = \frac{6 \sqrt{3} }{x} \\ x = \frac{6 \sqrt{3} }{ \sin(60) } = 12 \\ \tan(60) = \frac{6 \sqrt{3} }{y} \\ y = \frac{6 \sqrt{3} }{ \tan(60) } = 6[/tex]
