Answer:
Step-by-step explanation:
(x+1)(x-3)(x-4) = (x+1)(x²-7x+12) = x³-6x²+5x+12
:::::
(x+3)(x-0)(x-0)(x-5) = (x+3)(x²)(x-5) = (x²-2x-15)x² = x⁴-2x³-15x²
:::::
(x+2)³ = x³ + 3·x²·2 + 3·x·2² + 2³ = x³ + 6x² + 12x + 8
:::::
(x+3)²(x+1) = (x²+6x+9)(x+1) = x³ + 7x² + 15x + 9
